Is there a formula for figuring the weight of a pure lead round ball if the diameter is known?

TIA!

Don

Volume = 4 x pi x R x R x R / 3, or Volume = ( 4 x Pi x Radius ^ 3 ) / 3

, Pi, a universal constant = 3.1416

4 = 12.566

Radius = Diameter / 2 = 2 / 2 = 1

R^3 = R x R x R = 1

12.566 x 1 = 12.566

12.566 divided by 3 equals = 4.1887 cubic inches, the volume of a 2 inch ball.

4.1887 times the density of lead, which is 0.409 pounds per cubic inch, gives a weight of 1.713 pounds.

DaMan, This is from one of Sam Fadala's books.
(1) Cube the diameter of your RB, then multiply it by 0.5236. (Tis gives you the volume of a sphere/RB.)

(2) The resulting number is multiplied by 2,873.5 (The wt. in grains of 1 cu. in. of pure Pb.) The figure you get is the weight of your RB of dia. X in grains.

I tried Fadala's formula the other day and it works!