Calculating lead round ball weight?
Is there a formula for figuring the weight of a pure lead round ball if the diameter is known?
TIA!
Don
28 June 2007, 00:57
starmetalVolume = 4 x pi x R x R x R / 3, or Volume = ( 4 x Pi x Radius ^ 3 ) / 3
, Pi, a universal constant = 3.1416
4 = 12.566
Radius = Diameter / 2 = 2 / 2 = 1
R^3 = R x R x R = 1
12.566 x 1 = 12.566
12.566 divided by 3 equals = 4.1887 cubic inches, the volume of a 2 inch ball.
4.1887 times the density of lead, which is 0.409 pounds per cubic inch, gives a weight of 1.713 pounds.
26 July 2007, 01:55
Paul BraskyDaMan, This is from one of Sam Fadala's books.
(1) Cube the diameter of your RB, then multiply it by 0.5236. (Tis gives you the volume of a sphere/RB.)
(2) The resulting number is multiplied by 2,873.5 (The wt. in grains of 1 cu. in. of pure Pb.) The figure you get is the weight of your RB of dia. X in grains.
I tried Fadala's formula the other day and it works!