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Calculating lead round ball weight?
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posted 27 June 2007 23:18
Is there a formula for figuring the weight of a pure lead round ball if the diameter is known?

TIA!

Don
 
Posts: 49226 | Registered: 21 January 2001Reply With Quote
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posted 28 June 2007 00:57Hide Post
Volume = 4 x pi x R x R x R / 3, or Volume = ( 4 x Pi x Radius ^ 3 ) / 3

, Pi, a universal constant = 3.1416

4 = 12.566

Radius = Diameter / 2 = 2 / 2 = 1

R^3 = R x R x R = 1

12.566 x 1 = 12.566

12.566 divided by 3 equals = 4.1887 cubic inches, the volume of a 2 inch ball.

4.1887 times the density of lead, which is 0.409 pounds per cubic inch, gives a weight of 1.713 pounds.
 
Posts: 2864 | Registered: 23 August 2003Reply With Quote
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posted 26 July 2007 01:55Hide Post
DaMan, This is from one of Sam Fadala's books.
(1) Cube the diameter of your RB, then multiply it by 0.5236. (Tis gives you the volume of a sphere/RB.)

(2) The resulting number is multiplied by 2,873.5 (The wt. in grains of 1 cu. in. of pure Pb.) The figure you get is the weight of your RB of dia. X in grains.

I tried Fadala's formula the other day and it works!
 
Posts: 480 | Location: N.Y. | Registered: 09 January 2003Reply With Quote
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