Muzzle Energy Math Formula?

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12 November 2013, 02:29

D R Hunter

Muzzle Energy Math Formula?

Who can post the M.E. math formula please?
(Bullet weight, velocity, caliber, etc...)

D/R Hunter

Correct bullet placement, combined with the required depth of bullet penetration, results in an anchored animal...

12 November 2013, 03:23

pagosawingnut

I believe it is velocity times velocity times the bullet weight, then divide by 450400.

12 November 2013, 05:36

D R Hunter

Much appreciated!

D/R Hunter

Correct bullet placement, combined with the required depth of bullet penetration, results in an anchored animal...

16 November 2013, 04:36

sambarman338

Maybe I'm not holding my mouth right but I tried that method for the .450/.400

, multiplying the velocity by 400/7000 and alternatively by just 400 - and got nowhere near the 4000 ft/lb-odd needed.

Here are some formulae and the first two tables I came across by googling:

http://en.wikipedia.org/wiki/Muzzle_energy

http://www.chuckhawks.com/rifle_ballistics_table.htm

http://www.hornady.com/assets/...ndard-Ballistics.pdf

16 November 2013, 04:58

CCMDoc

Pagosa is, of course correct.
Using the 450-400 Hornady loading of a 400gr bullet at 2,050fps:

(2050 x 2050 x 400)/450240 = 3,733 ft-lbs

NRA Lifer; DSC Lifer; SCI member; DRSS; AR member since November 9 2003

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16 November 2013, 17:59

D R Hunter

Much Appreciated Gents!

D/R Hunter

Correct bullet placement, combined with the required depth of bullet penetration, results in an anchored animal...

19 November 2013, 00:24

pagosawingnut

YIPPEEEEE!!!
I got something right!!!