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one of us |
Most of you guys say that a bullet can not have more energy than the recoil that you feel when you shoot a rifle. Well have you think about this. If I shoot a .700 BMG IMPROVED in a 20 pounds rifle. And the recoil feels bad. How is it then to shoot the same cartridge it in a light rifle as 6 pounds. Will the bullet hit the target harder if I shoot it in the 6 pound rifle. For that recoil will kill me....??? | ||
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one of us |
Rusty...! The guys over here say that the bullet cant hit the target harder than the recoil can hit you. Sure my .460 has around 80-90 joule of recoil energy and it throw a 500 grain bullet at 2600 f/s and that give 10 000 joule. But that is a good question for the "experts" over here. Does a bullet hit harder if you shoot it from a lighter rifle wich have more recoil than a heavier one. If it have the same velocity from both | |||
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one of us |
A bullet of the same weight, and shape, traveling the same speed, will hit the target with the exact same FPE, no matter if it is shot from a 3 lb rifle, or a 20 lb rifle! If a rifle hit the shooter as hard as the bullet hit the target, then both animals, the shooter, and the moose, would be wounded the same amount. | |||
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one of us |
MacD37...! Yeah I know But some guys over here dont want to understand that a bullet will hit harder than the recoil of the rifle. Guys...! Please explain to me then...? Will the bullet energy be the same as the recoil of the rifle... | |||
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one of us |
I have always understood that recoil has no relation at all to the speed or impact of the bullet. Recoil is only related to the amount of energy generated in the chamber. A heavier bullet will naturally increase the tamping factor against the explosion, increasing energy in the opposite direction (felt recoil). Placing an explosive charge against a wall will do minimal damage. Placing an object against the explosive will create a tamping factor and increase the energy directed into the wall. Comparing recoil to bullet travel is like apples and oranges. | |||
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one of us |
If the rifle and the bullet are both of the same weigth then recoil velocity and energy would be the same and your shoulder would be history . This is a hard concept to under stand and I am not sure I will do it justice. As you know a rifle should weigh a certain amount. In my opinion they shuold all weigh more than 8 pounds. Upon firing the majority of the energy is transfered to the lightest weight. Not only is the weight of the rifle important but it is also placed against a simi solid object. You can do an easy experment on this effect shoot your rifle 2" off your shoulder. Back to the main issue the energy has to go some where and as the bullet is freed to move it acellerates up the barrel. This is not done instantly but over time however short. The bullet is gone by the time you can feel recoil. And fair percertage of recoil is the jet effect of powder gasses. How maney people can hold a hose of water with 50000 psi be hind it I Will wacth for the fun but from a safe distance | |||
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One of Us |
I would rather be hit by the rifle than the bullet | |||
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One of Us |
Not another energy question! My head still hurts from trying to figure out the last one. | |||
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one of us |
Guys...! Okey the reason to this topic that I have start is. We have talked about "stopping power" and then some guys have said that the bullet can not hit harder than the recoil of the rifle. "If the recoil cant knock over a barrel full of sand then the bullet cant" But now I see that it was just shit talk Those guys who have said that dont take this bad. | |||
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one of us |
The current issue of http://www.sportingrifles.com/ has some excellent info on recoil and energy. | |||
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<deranged-havoc-aficionado> |
quote:Hello overkill In my last post, and I can't even remember where, I think here, have serious sleep disorder>>deranged mental capacity, but have been thinking about this however inadequately. I think the guy Herald or Harald? forgot, I be sad mfer, is probably the one can explain best. BUT, I still no slouch in figuring out category, please try to find my last post. You said earlier that you had a source that said recoil would equal bullet energy impact. Please scan and post. There is the 'equal and opposite" thing, integrate the force over time, ya gonna get energy, the bullet just delivers its energy a hell of alot quicker. My last post deals with effects of caliber, speed, and energy sink over time-a very important variable-Probaobly THE most important, the other two are just what variables in the equation of energy sink over time.-been paining my brain on this, sad that I have to-it's getting daylight out, and just woke from short 'nap'. But specific hit, specific animal etc. etc., ya ain't gonna be able to analize, ya ain't gonna be able to spell worth a sh*%t that's where it just gonna be empiricle data, take what ya git, or not. I always take what data there be, otherwise, ya be fool. Data be nice thing if ya can understand. rob the vodka soaked data lover | ||
<Guesty> |
Does,nt Newtons law say that for every action there is an equal and opposite reaction ? I'm sure if the gun weighed the same as the projectile and the stock was the same size and shape of the projectile you would end up very Injured or dead as it would be hard to determine which end would become the projectile. Cheers Guesty | ||
<Harald> |
The force of the bullet hitting a barrel full of sand and the force of the rifle coming back into your shoulder will be similar (not necessarily the same). The force exerted on the bullet by the propellant gases in the bore is the same as that acting on the rifle. Energy is altogether different and does not pertain to how hard something hits. That is force. Energy is driven by the square of the velocity. Obviously the bullet is going much faster than the rifle, so even though it is quite small it will have roughly 100 times as much energy as the recoiling rifle. But I am so proud of Overkill's thought experiement that started this thread! He wondered aloud if changing the mass of the rifle would change the target impact and if not, questioned the idea of the two being the same. The main problem with that comparison is that these two things have a few connecting pieces missing (like the propellant gases that vented from the muzzle) and there is no law that says energies are equal and opposite. However, here is a weird fact for you. If the rifle is held absolutely rigid and not allowed to recoil, then the muzzle velocity of the bullet will be increased by the amount equivalent to the recoil energy that was not spent. It would be about 0.5% more velocity, so nothing you would ever be likely to measure, given the typical shot to shot variations. Strange no? The total energy of the system must be conserved. It all goes somewhere, so if one source is removed (the recoil) it must be reallocated to another element (the velocity of the bullet and gases). [ 08-06-2002, 06:55: Message edited by: Harald ] | ||
one of us |
Overkill- Your right! the recoil of a 700 Improved shooting 1900 gr bullets at 2000 fps in a 6 lb rifle will kill you! don't let anyone convince you otherwise!-Rob | |||
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<Wes> |
Overkill, There are two different laws of phsics to mathematically describe what you are describing. One, conservation of momentum and two, conservation of energy. Either is valid. With momentum, it says the mass of the projectile times the velocity of the projectile equals the mass of the gun times the velocity of the gun. Additional considerations are the mass / velocity of powder or the mass of the shooters shoulder. Conservation of energy uses velocity squared on each side, so the lighter object gets most of the energy, something on the order of the ratio of the gun weight divided by the bullet weight. Not fully intuitive at first glance, but both are satisfied. apologies that my physics are rusty and I'm too lazy to go look it up. Whenever I read "power" I usually skip the rest, as now we're into the subjective and infinite vagaraties of human preference, perception, and opinion. Facts only confuse things at that point. That much being said... Myself, I use a formula of Power = bullet mass times bullet energy, or P=M^2V^2. Reasons as follows. One, it directly relates to what my shoulder feels, which I feel is as valid a punch, knockout, whatever as any method. (and none are really totally valid) Use this formula for an '06, .375, or .223 or whatever and, for the same gun weight, the relative recoil values will exactly relate to the M2V2 values. I can thus look at a load, look up the energy, and, knowing the projectile weight get a very accurate idea of how my shoulder will feel plus some index of down range effect. Projectile M2V2/gun weight is basicly the gun recoil energy equation, available lots of places. Not sure I'm adding mud or water Wes | ||
one of us |
What is the answer...? Can the bullet have more push "punch" energy than the recoil of the rifle...? Yes or No??? | |||
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<Wes> |
The bullet has the same momentum as the rifle but a lot more kinetic energy (see previous). A .375 makes about 45 ft.lbs recoil energy in an 8 pound gun, but the bullet has 4500lbs, about 100:1. 300 grains is about 3/4 Oz and the gun is 128 Oz, so that's about 160 to 1. Powder makes 1/3 (give or take) of the recoil energy, so about 100:1 again, which is about right, everything according to plan. Absorbing a bullet, from an external standpoint, is an inelastic collision (target and projectile merge into one peice and stay that way), so we use the momentum equation to determine the outcome. If it were elastic (the objects bounce off from each other) we'd use the energy. So.. If someone caught a .375 bullet using an 8 pound stick on their shoulder, they would feel a bit less of a whallop than what a what the shooter felt for "recoil punch". Reason being is the shooters shoulder had to launch the powder charge plus projectile and the shooteee just had to catch the projectile. By the way, I'd still rather be the shooter. Where does all that kinetic energy go? It heats the stick a bit. Shooting water jugs gives the impression of lots of power. Try shooting at a pile of week old spring snow with a .375. If the pile is more than a 3 foot ball of hand packed wet corn snow, it will absorb a (speer 235 at 2900 fps) bullet with absoloutely no observable effect, and the bullet will not emerge out the other side. It's humbling. Made me re-think my plans for knocking off the neighborhood snow men. Wes | ||
<deranged-havoc-aficionado> |
quote:OK, now I be really feeling ignorant, being from central texas, snow ain't exactly something we be dealing with much, are you an eskimo? What in god's name is wet corn snow, the wet part I can understand, I've skied alot, but what is the corn part, is that when it be getting kinda pebbly? I be thinking you up there with harald in your physics. I wish I could grasp the momentum-vs-KE thing, but my physics be too far long ago. I still think though that you can integrate over time, but I just ain't got the patience to think it through. rob the guy obviously be damn lazy | ||
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