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<mike aw> |
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<Dave King> |
You didn't have a wind velocity and I assumed a 10 mph crosswind, temp 59 degres, altitude 500ft ASL. 500 yards 23.3 inches 5 mph = 1/2 that amount, 20 mph = twice that amount. Change the altitude to 5000 ft ASL, 59 degrees 10 mph. 500 yards 18.9 inches
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<monz> |
Try www.norma.cc | ||
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